100x^2+6x-150=0

Solution for 100x^2+6x-150=0 equation:

100x^2+6x-150=0

a = 100; b = 6; c = -150;
Δ = b2-4ac
Δ = 62-4·100·(-150)
Δ = 60036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60036}=\sqrt{4*15009}=\sqrt{4}*\sqrt{15009}=2\sqrt{15009}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{15009}}{2*100}=\frac{-6-2\sqrt{15009}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{15009}}{2*100}=\frac{-6+2\sqrt{15009}}{200}
$